FeedBack Form

Your Name :
Your Email :
Your Location :
Your Message :
   
FeedBack

Average Problems

AVERAGE -> IMPORTANT FACTS AND FORMULAE

I. Average = [Sum of observations / Number of observations]
II. Suppose a man covers a certain distance at x kmph and an equal distance at y kmph. Then, the average speed during the whole journey is [2xy / x + y] kmph.

AVERAGE -> SOLVED EXAMPLES

1. Find the average of all prime numbers between 30 and 50.
  Sol. There are five prime numbers between 30 and 50.
They are 31, 37, 41, 43 and 47.
∴ Required average = [(31 + 37 + 41 + 43 + 47) / 5] = 199/5 = 39.8.
2. Find the average of first 40 natural numbers.
  Sol. Sum of first n natural numbers = 40 * 41 / 2 = 820.
∴ Required average = 820 / 40 = 20.5.
3. Find the average of first 20 multiples of 7.
  Sol. Required average = 7(1+2+3 ... + 20) / 20 = [7 * 20 * 21 / 20 * 2] = [147 / 2] = 73.5.
4. The average weight of 10 oarsmen in a boat is increased by 1.8 kg when one of the crew, who weighs 53kg is replaced by a new man. find the weight of the new man.
  Sol. Total weight increased = (1.8 * 10)kg = 18kg.
∴ Weight of the new man = (53 + 18)kg = 71kg.
5. A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. find his average after 17th inning.
  Sol. Let the average after 17th inning = x.
Then, average after 16th inning = (x - 3)
∴ 16(x - 3) + 87 = 17x or x = (87 - 48) = 39.

Average -> EXERCISE

16. In Prasanna's opinion, his weight is greater than 65 kg but less than 72 kg. His brother does not agree with Prasanna and he thinks that Prasanna's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all of them are correct in their estimation, what is the average of different probable weights of Prasanna?
 
  • A. 67 kg
  • B. 68 kg
  • C. 66.5 kg
  • D. 69 kg
Ans: C.
Sol.
Let Prasanna's weight be X kg.
According to Prasanna, 65 < X < 72.
According to Prasanna's brother, 60 < X < 70.
According to Prasanna's mother, X < 68.
The value satisfying all the above conditions are 66 and 67.
∴ Required average = [ 66 + 67 / 2 ] = [133 / 2] = 66.5 kg.
 
17. In a school with 600 students, the average age of the boys is 12 years and that of the girls is 11 years. If the average age of the school is 11 years 9 months, then the number of girls in the school is
 
  • A. 150
  • B. 200
  • C. 250
  • D. 350
Ans: A.
Sol.
Let the number of grils be x.
Then, number of boys = (600 - x).
Then, (11 3/4 × 600)
⇔ 11x + 12(600 - x) ⇔ x = 7200 - 7050 ⇔ 150.
 
 
18. In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
 
  • A. 6.25
  • B. 6.5
  • C. 6.75
  • D. 7
Ans: A.
Sol.
Required run rate = 282 - (3.2 x 10) / 40 = 250/40 = 6.25.