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16.	Saranvanan starts walking straight towards east. After walking 75 metres, he turns to the left and walks 25 metres straight. Again he turns to the left, walks a distance of 40 metres straight, again he turns to the left and walks a distance of 25 metres. How far is he from the starting point?
	A. 25 metres B. 35 metres C. 45 metres D. 55 metres

Answer

Explanation

Ans: B.

Sol.

The movements of Deepak are as shown in Fig.
Clearly EB = DC = 40m.
Saravanan’s distance from the starting point A
= (AB – EB)
= ( 75 – 40 ) m
= 35m.

17.	I am facing South. I turn right and walk 20 m. Then I turn right again and walk 10 m. Then I turn left and walk 10 m and then turning right walk 20 m. Then I turn right again and walk 60 m. In which direction am I from the starting point?
	A. East B. North–west C. West D. North–east

Answer

Explanation

Ans: D.

Sol.

The movements of the person are from A to F. as shown in Fig.
Clearly, the final position is F which is to the North east of the starting point A.

18.	Rohit walked 25 metres towards South. Then he turned to his left and walked 20 metres. He then turned to his left and walked 25 metres. He again turned to his right and walked 16 metres. At what distance is he from the starting point and in which direction?
	A. 35 metres East B. 35 metres North C. 40 metres East D. 60 metres East

Answer

Explanation

Ans: A.

Sol.

The movements of Rohit are as shown in Fig.
Rohits distance from starting point A
= AE = ( AD + DE )
= ( BC + DE )
= ( 20 + 15 )m
= 35 m.
Also, E is to the East of A.

19.	X and Y start moving towards each other from two places 200 m apart. After walking 60 m, B turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If A and B walk with the same speed, what is the distance between them now?
	A. 20 m B. 30 m C. 40 m D. 50 m

Answer

Explanation

Ans: C.

Sol.

Clearly Y moves 60 m from Q upto A, then 20 m upto B, 40 m upto C and then upto D.
So, AD – BC = 40 m.
QD = (60 + 40) m = 100 m.
Since A and B travel with the name speed, A will travel the same speed along the horizontal as B travels in the same time. i.e. (60 + 20 + 40 + 20) = 140 m.
So. X travels 140m upto A.
Distance between X and Y = AD – (100 – 60) m = 40 m.

20.	Suriya walks 10 metres towards the South. Turning to the left, he walks 20 metres and then moves to his right. After moving a distance of 20 metres, he turns to the right and walks 20 metres. Finally, he turns to the right and moves a distance of 10 metres. How far and in which direction is he from the starting point?
	A. 10 metres North B. 20 metres South C. 20 metres North D. 10 metres South

Answer

Explanation

Ans: B.

Sol.

The movements of Sanjeev from A to F are as shown in Fig.
Clearly, Suriya's distance from starting point A
= AF = (AB + BF)
= AB + (BE – EF)
= AB + (CD – EF)
= [10 + (20 – 10)]= (10 + 10) m =20 m.
Also, F lies to the South of A.
So, Suriya is 20 metres to the south of his starting point.

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